[Python] Baekjun 1000 times - A+B

BaekJoon 1000

Solution

A, B = input().split()

print(int(A) + int(B))

input()

• When input as input(), it is saved as a string.

Another solution

a, b = map(int, input().split())

You can receive it directly as int.

a, b = int(input().split()) # 잘못된 풀이

-> Since the result of input().split() is in the form of a list, an error occurs if the list is wrapped with int().

map() function

• A tool that applies the “same function” to multiple values in a list at once

  map(함수, 반복 가능한 데이터)
  

  ``` python

  예시

  nums = [1, 2, 3]

result = map(int, nums) # nums 안에 있는 값들 하나씩 꺼내서 int() 적용 print(list(result)) # [1, 2, 3] ```

• Things to note
  • If I print it right away, it doesn’t come out.
  • If you immediately output the object to which map() is applied, a strange object appears because the corresponding value outputs a map object (iterator). - Therefore, if you want to output the value to which map is applied, type conversion is required, such as wrapping it once with list() and outputting it in list form. - Use it once and you’re done (iterator feature) ``` python a = map(int, [1,2,3])

  print(list(a)) # [1,2,3] print(list(a)) # [] (이미 다 써버림) ```